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Task 48
Duplicate check
GROUP BY + HAVING COUNT(*) > 1 finds duplicates.
Task
How do you spot duplicate values in a column?
The editor already contains a starting point. Change it until every check passes — the Next task button unlocks when it does.
What you start with
SELECT city, COUNT(*) AS total FROM students GROUP BY city HAVING COUNT(*) > 1;
Syntax reference
SELECT city, COUNT(*) AS total FROM students GROUP BY city HAVING COUNT(*) > 1;
Read it, then write it yourself. Copy-paste teaches nothing.
The sample database
CREATE TABLE courses (id INTEGER PRIMARY KEY, title TEXT, monthly_fee INTEGER); CREATE TABLE students (id INTEGER PRIMARY KEY, name TEXT, city TEXT, course_id INTEGER, joined TEXT); CREATE TABLE fees (id INTEGER PRIMARY KEY, student_id INTEGER, month TEXT, amount INTEGER, paid INTEGER); INSERT INTO courses VALUES (1,'Web Design',9000),(2,'Python',11667),(3,'JavaScript',11667),(4,'AI & Prompt Engineering',15000); INSERT INTO students VALUES (1,'Sara','Faisalabad',2,'2026-01-12'), (2,'Ali','Faisalabad',1,'2026-01-20'), (3,'Hina','Jhumra',2,'2026-02-02'), (4,'Bilal','Faisalabad',4,'2026-02-15'), (5,'Ayesha','Sargodha',3,'2026-03-01'), (6,'Usman','Jhumra',1,'2026-03-11'), (7,'Zainab','Faisalabad',4,'2026-04-05'), (8,'Hamza','Faisalabad',3,'2026-04-19'); INSERT INTO fees VALUES (1,1,'2026-01',11667,1),(2,1,'2026-02',11667,1), (3,2,'2026-01',9000,1),(4,2,'2026-02',9000,0), (5,3,'2026-02',11667,1),(6,3,'2026-03',11667,0), (7,4,'2026-02',15000,1),(8,4,'2026-03',15000,1), (9,5,'2026-03',11667,0), (10,6,'2026-03',9000,1),(11,6,'2026-04',9000,0), (12,7,'2026-04',15000,0), (13,8,'2026-04',11667,1);
SQL
1 automatic check Section 5 · Real academy queries
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Hint
Ask yourself: How do you spot duplicate values in a column?
Still stuck? Open “Syntax reference” in the left column, then type it yourself and change one value.